The Cable Supporting A 2125 Kg Elevator

We use Newton’s second law of motion here, which states that, F=ma where: F is the force applied in newtons m is the mass of the object in kilograms a is the acceleration of the object in meters per second squared So we get: a=F/m =(21750 \ “N”)/(2100 \ “kg“) ~~10.36 \ “m/s”^2

SOLVED: An elevator is suspended with a cable and its mass is 986.9 kg. If the maximum acceleration of the elevator is 0.2 m/s^2 and the breaking stress is 3.14 x 10^8

May 25, 2023Expert-Verified Answer question No one rated this answer yet ā€” why not be the first? šŸ˜Ž malikmemoona395 The maximum upward acceleration the cable can provide without breaking is 10.24 m/sĀ². How to calculate maximum upward acceleration of elevator cable?

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Science Physics Physics questions and answers 6. (II) The cable supporting a 2125āˆ’kg elevator has a maximum strength of 21,750 N. What maximum upward acceleration can it give the elevator without breaking? 8. (II) A train locomotive is pulling two cars of the same mass behind it, Fig. 4-47.

SOLUTION: Newton s motion law exercise - Studypool
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SOLVED: 12 An elevator cab of mass m = 500 kg is descending with speed V; = 4.0 m/s when its supporting cable begins to slip, allowing it to fall with constant

Is it possible that the cable supporting the alligator has a maximum strength of 21 7 15? The elevator can give the maximum upward acceleration without breaking. This is how the elevator looks if we try to draw … The cable supporting a 2125-kg elevator has a maximum strength of 21,850 N. What maximum upward acceleration can it give the

68. A 1000 kg lift is supported by a cable that can support 2000 kg. The  shortest distance in which the lift can be stopped when it is descending  with a speed
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The Cable Supporting A 2125 Kg Elevator

Is it possible that the cable supporting the alligator has a maximum strength of 21 7 15? The elevator can give the maximum upward acceleration without breaking. This is how the elevator looks if we try to draw … The cable supporting a 2125-kg elevator has a maximum strength of 21,850 N. What maximum upward acceleration can it give the
Newton’s Laws of Motion 5. The cable supporting a 2125-kg elevator has a maximum strength of 21,750 N. What maximum upward acceleration can it give the elevator without breaking? Problem 24CQ: A cartoon shows the toupee coming off the head of an elevator passenger when elevator rapidly stops

68. A 1000 kg lift is supported by a cable that can support 2000 kg. The shortest distance in which the lift can be stopped when it is descending with a speed

And a cable force minus gravity divided by m. So, that’s cable force minus mg divided by m, substituting for gravity there. And that’s 21750 Newtons maximum cable force up minus 2125 kilograms mass of the elevator times 9.8 Newtons per kilogram, all divided by the mass of the elevator, 2,125 kilograms which is 0.44 m/s squared upwards.

An elevator of mass 2000 kg is accelerating upward. If the upward tension in supporting cable is 29000 N, what is the upward acceleration? – Quora

An elevator of mass 2000 kg is accelerating upward. If the upward tension  in supporting cable is 29000 N, what is the upward acceleration? - Quora
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Solving Problems Calculating Vertical Tension Forces on a Static Object | Physics | Study.com

And a cable force minus gravity divided by m. So, that’s cable force minus mg divided by m, substituting for gravity there. And that’s 21750 Newtons maximum cable force up minus 2125 kilograms mass of the elevator times 9.8 Newtons per kilogram, all divided by the mass of the elevator, 2,125 kilograms which is 0.44 m/s squared upwards.

Solving Problems Calculating Vertical Tension Forces on a Static Object |  Physics | Study.com
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SOLVED: An elevator is suspended with a cable and its mass is 986.9 kg. If the maximum acceleration of the elevator is 0.2 m/s^2 and the breaking stress is 3.14 x 10^8

We use Newton’s second law of motion here, which states that, F=ma where: F is the force applied in newtons m is the mass of the object in kilograms a is the acceleration of the object in meters per second squared So we get: a=F/m =(21750 \ “N”)/(2100 \ “kg“) ~~10.36 \ “m/s”^2

SOLVED: An elevator is suspended with a cable and its mass is 986.9 kg. If  the maximum acceleration of the elevator is 0.2 m/s^2 and the breaking  stress is 3.14 x 10^8
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SOLVED: 12 An elevator cab of mass m = 500 kg is descending with speed V; = 4.0 m/s when its supporting cable begins to slip, allowing it to fall with constant

Science Physics Physics questions and answers 6. (II) The cable supporting a 2125āˆ’kg elevator has a maximum strength of 21,750 N. What maximum upward acceleration can it give the elevator without breaking? 8. (II) A train locomotive is pulling two cars of the same mass behind it, Fig. 4-47.

SOLVED: 12 An elevator cab of mass m = 500 kg is descending with speed V; =  4.0 m/s when its supporting cable begins to slip, allowing it to fall with  constant
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A worker develops a tension $T$ in the cable as he attempts | Quizlet

Sep 20, 2022Question Answered step-by-step The cable supporting a 2125 āˆ’ k g elevator has a maximum strength of 21, 750 N. What maximum upward acceleration can it give the elevator without breaking? Instant Solution: Step 1/6 Step 1: First, we need to identify the given values.

A worker develops a tension $T$ in the cable as he attempts | Quizlet
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SOLUTION: Newton s motion law exercise – Studypool

Is it possible that the cable supporting the alligator has a maximum strength of 21 7 15? The elevator can give the maximum upward acceleration without breaking. This is how the elevator looks if we try to draw … The cable supporting a 2125-kg elevator has a maximum strength of 21,850 N. What maximum upward acceleration can it give the

SOLUTION: Newton s motion law exercise - Studypool
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The cable supporting a 2125-kg elevator has a maximum strength of 21,750 N. What maximum upward acce – YouTube

Newton’s Laws of Motion 5. The cable supporting a 2125-kg elevator has a maximum strength of 21,750 N. What maximum upward acceleration can it give the elevator without breaking? Problem 24CQ: A cartoon shows the toupee coming off the head of an elevator passenger when elevator rapidly stops

The cable supporting a 2125-kg elevator has a maximum strength of 21,750 N.  What maximum upward acce - YouTube
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Solving Problems Calculating Vertical Tension Forces on a Static Object | Physics | Study.com

The cable supporting a 2125-kg elevator has a maximum strength of 21,750 N. What maximum upward acce – YouTube

May 25, 2023Expert-Verified Answer question No one rated this answer yet ā€” why not be the first? šŸ˜Ž malikmemoona395 The maximum upward acceleration the cable can provide without breaking is 10.24 m/sĀ². How to calculate maximum upward acceleration of elevator cable?

SOLVED: 12 An elevator cab of mass m = 500 kg is descending with speed V; = 4.0 m/s when its supporting cable begins to slip, allowing it to fall with constant SOLUTION: Newton s motion law exercise – Studypool

Sep 20, 2022Question Answered step-by-step The cable supporting a 2125 āˆ’ k g elevator has a maximum strength of 21, 750 N. What maximum upward acceleration can it give the elevator without breaking? Instant Solution: Step 1/6 Step 1: First, we need to identify the given values.